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Is AC current fundamentally better as a working current when it comes to amplifying audio signal?
No. If anything, using an AC power supply makes it more difficult to have low noise.
The circuits that handle audio are all powered by DC. So any amplifier that has an AC power input has to convert this to DC internally. The AC cabling inside the amplifier ...
5
The type of current is actually completely irrelevant as all transmitted power is AC. Unless you are driving your amplifier from batteries, everything has to be converted at some point to DC.
The end result all boils down to the amount of power you need to draw from the supply in order to amplify the audio to the level you require.
The main reason why AC ...
5
It's more about practicality than of necessity.
Imagine a guitar with one pickup and no volume or tone knobs.
You're right, this would produce slightly less noise (probably less than the noise floor you'd get on any recording - but in theory any component passive component will add some noise).
However, you would probably want control your volume/gain ...
4
Another consideration: assuming your guitar has at least two sets of pickups, if you didn't have what's essentially a mixer on/in your axe, you'd need to pass more wires to the remote preamp. That not only increases the complexity of the patch cord but increases the risk of crosstalk and interference pickup.
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Compression followed by expansion is often called "companding" and is used in various fields to reduce noise. It is effective in reducing the final level of noise that is introduced between the compression and expansion steps. It will do nothing to improve noise introduced after expansion, and could make noise introduced before compression worse, or leave it ...
2
I'm presuming you mean something like this (the blue waveform): -
The red waveform is amplitude modulation and the blue waveform is frequency modulation.
This should be the formula you need: -
y(t) is the FM output
fc is the unmodulated carrier frequency
f(delta)/fm is the modulation index - see this wiki article
fm is the modulating frequency
t is time
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You need to divide the part of the mono cable dedicated to the Tip into two equal copper cables and solder one to the Tip and the other one to the Ring part of your TRS jack (stereo) the other cable stays on the Sleeve.
2
The role of an audio power amplifier (be it a traditional hi-fi amplifier, the embedded amplifier in powered loudspeakers, or the small amplifier that drives the headphones of your smartphone) is to provide the electrical power to physically move the speakers (not all of them are properly loudspeakers, but for simplicity I'll just say speakers). Radio waves ...
1
Supported codecs and containers for the audioread function of matlab can be found at:
https://www.mathworks.com/help/matlab/ref/audioread.html
1
Thing is, that if two points in a circuit are actually "ground" (i.e. 0V potential) then by definition, no current can flow between these two points.
When current does flow between two arbitrary points on a circuit (that we may consider to be 'ground') this actually means that one or another of these points is actually not ground. Only one of them is. ...
1
These spikes are high frequency components contained in the resulting signal decode. There are two possible reasons for this.
Method one uses a low pass filter which removes these components.
Method two has a decoding fault.
Both of these suggestions are speculative as there is no reference signal to compare.
1
You can't change the signal level that that's recorded from Logic, Logic will record the signal it gets bit for bit. You can change the monitoring level in Logic and that's what you're hearing when you adjust the levels in Logic while tracking. The way to control your signal level that's recorded is right from your Apollo, the big knob adjusts your relevant ...
1
A balanced line-level output usually has TRS (tip-ring-shield) 1/4" connectors. Connecting them to an unbalanced input requires the use of mono cables which short R with S (ring/return with shield) in the TRS socket.
This balanced->imbalanced conversion works only at the jack level, not at the socket level: a mono socket has only "T" (tip) and "S" (shield) ...
1
Sounds like induction whine to me, certainly not a ground loop, which is always at either 50 or 60Hz, depending on what country you're in.
50Hz can be seen on a guitar tuner as roughly G#, never tested what 60Hz looks like.
Induction whine is generated by some external device, TV, fridge, lighting, even something like a phone or wifi, though phones tend to ...
1
According to the service manual (available on the AKG website) the phantom power is 3.9v and is connected to pin 3, so the microphone connector should have pins 2 and 3 shorted. If I understand this correctly, the included cable won't have this short and will only connect pin 1 (ground) and pin 2 (signal) so there shouldn't be any risk. I have used the PT 40 ...
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With a condenser microphone the 48-volt DC is applied to both audio lines, so it cancels out because the signal is sent as a difference between those two lines. With a headset jack the signal for each speaker is sent as the offset between a conductor and the ground line -- this is the same circuit as that used for delivering the phantom power. As a result ...
1
A DI-box would do the job, for example most of these would. Look in the specs if it supports speaker output (usually the maximum wattage is specified).
Note that most of them are mono, so look for a stereo version or hook up two of them parallel.
Also look at the voltage (if it is an active one), you need 12V for most cars.
Most DI-box's have balanced ...
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