I have been asked to solve this exercise.

An environment of $V=1500$ $m^3$, it is considered a reverberated field acoustic pressure level of $70$ $dB$ when an acoustic source of $80$ $dB$ is activated. Compute the total absorption (in $m^2$) in order to obtain a reverberation time of $4$ seconds.

Let me show you my idea: I have to use Sabine's formula $$ T_{60} = \beta \frac{V}{A} \text{ with } \beta=0.16$$

The surface $A$ should be computed as

$$A = \sum_i a_i S_i $$

where $a_i$ is the absorption coefficient of the $i$-th surface $S_i$.

Can someone help me to find the missing surfaces and coefficients because I can't understand in which way I must find them?

Thanks in advance.


1 Answer 1


Sabin formula for Reverberation Time:

enter image description here

You know the target RT and the volume of the room. What you are looking for is the total absorption A, S is just a surface area. Technically, the unit of A is called Sabine, not squared meters. So rearrange the equation and solve it:

enter image description here


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.